Question

10y^2+10y+3=0 use quadratic formula to solve each equation ​

Answer 1

Answer:
`\bold{-(1)/(2)\pm (\sqrt5)/(10)}i`

Explanation:

`10y^2+10y+3=0\qquad \rightarrow \quad a=10,\ b=10,\ c=3\\\\y=(-b\pm √(b^2-4ac))/(2a)\\\\\\y=(-10\pm √(10^2-4(10)(3)))/(2(10))\\\\\\.\ =(-10\pm √(100-120))/(2(10))\\\\\\.\ =(-10\pm √(-20))/(2(10))\\\\\\.\ =(-10\pm 2i\sqrt5)/(2(10))\\\\\\.\ =(-5\pm i\sqrt5)/(10)\\\\\\.\ =-(1)/(2)\pm (\sqrt5)/(10)i`