Question

A gas occupies 72.1 at stp. At what temperature would the gas occupy 85.9 L at a pressure of 93.6 kPa?

Answer 1

To solve for the temperature at which the gas occupies a given volume at a given pressure, we can use the ideal gas law equation PV = nRT.

Step-by-step explanation:

To solve this problem, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to find the number of moles of gas using the given information. Since the gas occupies 72.1 L at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to calculate the number of moles: n = 72.1 L / 22.4 L/mol = 3.21 mol.

Next, we can rearrange the ideal gas law equation to solve for the temperature: T = PV / (nR). Plugging in the values we have, T = (93.6 kPa)(85.9 L) / (3.21 mol)(8.31 J/mol·K) = 277 K.

Answer 2

328.1 K.

Step-by-step explanation:

• To calculate the no. of moles of a gas, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in.

• If n is constant, and have two different values of (P, V and T):

P₁V₁T₂ = P₂V₂T₁

P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).

P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.

T₂ = P₂V₂T₁/P₁V₁ = (0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) = 328.1 K.