Question

I need help please? thank you :)

Answer 1

Break into two parts and simplify

`\\ \rm\dashrightarrow (z^2-14z+48)/(z^2+6z-27)`

`\\ \rm\dashrightarrow (z^2-8z-6z+48)/(z^2+9z-3z-27)`

`\\ \rm\dashrightarrow ((z-8)(z-6))/((z+9)(z-3))`

Now divide by the denominator

`\\ \rm\dashrightarrow ((z-8)(z-6)(z-3))/((z+9)(z-3)(z-8))`

`\\ \rm\dashrightarrow (z-6)/(z+9)`

Answer 2

`{\qquad\qquad\huge\underline{{\sf Answer}}}`

Here we go ~

`\qquad \sf  \dashrightarrow \: \cfrac{ {z}^(2) - 14z + 48 }{ {z}^(2) + 6x - 27} ÷ \cfrac{z -8}{z-3}`

`\qquad \sf  \dashrightarrow \: \cfrac{ {z}^(2) - 8z - 6z+ 48 }{ {z}^(2) + 9z- 3z- 27} ÷ \cfrac{z -8}{z-3}`

`\qquad \sf  \dashrightarrow \: \cfrac{ {z(}^{} z- 8) - 6(z - 8) }{ {z}^{} (z+ 9)- 3(z + 9)} ÷ \cfrac{z -8}{z-3}`

`\qquad \sf  \dashrightarrow \: \cfrac{ {(}^{} z- 8) (z - 6) }{ {}^{} (z+ 9)(z - 3)} ÷ \cfrac{z -8}{z-3}`

`\qquad \sf  \dashrightarrow \: \cfrac{ (z - 6) }{ {}^{} (z+ 9)}`