Question

26.10 mL of a 0.250 M potassium carbonate solution is reacted with excess hydroiodic acid. How many grams of gas formed are in the balanced equation

Answer 1

Below in bold.

Step-by-step explanation:

The equation is:

K2CO3 + 2HCl ----> 2KCl + CO2 + H2O

So 1 mole of K2CO3 produces 1 mole of CO2.

Number of moles of K2CO3 in the solution

= 0.25 * 26.10 / 1000

= 0.00625 moles

This produces 0.00625 moles of CO2

which is 0.00625*44

= 0.2871 grams.