Answer:
+e
Step-by-step explanation:
The charge of an up quark is:
![q_u = +(2)/(3)e](https://img.qammunity.org/2020/formulas/physics/high-school/luvuaxcgahq067kx1gq1phb9pmz4y8o9xd.png)
The charge of a down quark, instead, is:
![q_d = -(1)/(3)e](https://img.qammunity.org/2020/formulas/physics/high-school/y4al3qcu8srlfagisiovj2kjpxotsjbmzj.png)
In this problem, we have a particle consisting of 1 down quark and 2 up quarks, Therefore, the net charge of the particle will be
![q=1(q_d)+2(q_u)=1(-(1)/(3)e)+2((2)/(3)e)=-(1)/(3)e+(4)/(3)e=(3)/(3)e=+e](https://img.qammunity.org/2020/formulas/physics/high-school/vr6r70kijyo1ju6by2yz13nrl4dz25rpqa.png)
So, the particle has a charge of +e.