Question

Write the equation of a circle with center of (5,-3) and a radius of 4​

Answer 1

`\large\boxed{(x-5)^2+(y+3)^2=16}`

Explanation:

The standard form of an equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

(h, k) - center

r - radius

We have the center (5, -3) and the radius r = 4. Substitute:

`(x-5)^2+(y-(-3))^2=4^2\\\\(x-5)^2+(y+3)^2=16`