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Write the equation of a circle with center of (5,-3) and a radius of 4​

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Answer:


\large\boxed{(x-5)^2+(y+3)^2=16}

Explanation:

The standard form of an equation of a circle:


(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the center (5, -3) and the radius r = 4. Substitute:


(x-5)^2+(y-(-3))^2=4^2\\\\(x-5)^2+(y+3)^2=16

User Daniel Mora
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