Answer:
Connect them in parallel
Step-by-step explanation:
The energy stored by two capacitors connected to the same voltage source is given by
![U=(1)/(2)C_T V^2](https://img.qammunity.org/2020/formulas/physics/high-school/n8ffy6fdy73v99j7i8l43h0lwe3zu1lqyd.png)
where
is the total capacitance of the two capacitors
V is the voltage of the source
In order to maximize the energy stored U, we need to maximize
. We have:
- In parallel, the total capacitance is given by the sum of the individual capacitances:
![C_T(p) = C_1 + C_2](https://img.qammunity.org/2020/formulas/physics/high-school/srzcg1j8jzggy96n8u3xbrv1p3qhwixhcq.png)
- In series, the total capacitance is given by:
![C_T(s)=(1)/((1)/(C_1)+(1)/(C_2))](https://img.qammunity.org/2020/formulas/physics/high-school/u91pho3qne9dpfc1jm0uzxhpsefy04t4ww.png)
Comparing the two equations, we notice that
, so the parallel configuration is the one that maximizes the energy stored.