Question

Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave radiation?

Answer 1

`1.63\cdot 10^(-24) J`

Step-by-step explanation:

The energy of a photon is given by:

`E=(hc)/(\lambda)`

where

h is the Planck constant

c is the speed of light

`\lambda` is the wavelength of the photon

In this problem, we have a microwave photon with wavelength

`\lambda=12.2 cm=0.122 m`

Substituting into the equation, we find its energy:

`E=((6.63\cdot 10^(-34) Js)(3\cdot 10^8 m/s))/(0.122 m)=1.63\cdot 10^(-24) J`