Question

How many vibrations per second are associated with a 101-mhz radio wave?

Answer 1

`1.01\cdot 10^8` vibrations per second

Step-by-step explanation:

The frequency of a wave corresponds to the number of vibrations per second:

`f=(N)/(1 s)` (1)

where N is the number of vibrations per second.

In this problem, the frequency of the radio wave is

`f=101 MHz =1.01\cdot 10^8 Hz`

And substituting into eq.(1), we find N:

`N=f \cdot (1 s)=1.01\cdot 10^8`