Question

Find the solution to Y=-x^2+3 for X=-3,0, and 3

Answer 1

3-,3,0,3

Explanation:

Answer 2

For this case we must evaluate the following quadratic equation,
`y = -x ^ 2 + 3,` for
`x = -3`,
`x = 0`and
`x = 3`

For
`x = -3`:

`y = - (- 3) ^ 2 + 3\\y = -9 + 3 =\\y = -6`

For
`x = 0`:

`y = - (0) ^ 2 + 3\\y = 0 + 3\\y = 3`

For
`x = 3`:

`y = - (3) ^ 2 + 3\\y = -9 + 3\\y = -6`

Answer:

`(-3, -6)\\(0,3)\\(3, -6)`