We can calculate the new volume of the gas using the Combined Gas Law:
(P1 x V1) / T1 = (P2 x V2) / T2
The initial volume, pressure, and temperature were 280 mL, 1.3 atm, and 291.15 K (changing the temperature into Kelvin is necessary), and the final volume, pressure, and temperature is V2, 3.0 atm, and 308.15 K. Plugging these values in and solving, we find that:
(P1 x V1) / T1 = (P2 x V2) / T2
(1.3 atm x 280 mL) / 291.15 K = (3.0 atm x V2) / 308.15 K
V2 = 128.42 mL
This makes sense considering the conditions, a small increase in temperature would make the gas expand but a significant increase in the pressure would cause the volume to decrease.
Hope this helps!