Question

What is the magnetic field strength, in units of microTesla (T), at a distance of 6.3 cm from a long straight wire carrying a current of 6.5 A?

Answer 1

`2.1 \mu T`

Step-by-step explanation:

The magnetic field strength is given by:

`B=(\mu_0 I)/(2 \pi r)`

where

`\mu_0` is the vacuum permeability

I is the current

r is the distance from the wire

In this problem,

I = 6.5 A

r = 6.3 cm = 0.063 m

So, the magnetic field strength is

`B=((1.256\cdot 10^(-7) H/m)(6.5 A))/(2 \pi (0.063 m))=2.1\cdot 10^(-6) T=2.1 \mu T`