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There are 5 players in a baseball lineup. How many different batting orders are possible for these 5 players? (use FACTORIALS to find the probability of the number of permutations)

User Managerger
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5.8k points

2 Answers

4 votes

Answer:

5! or 120.

Explanation:

Think about this logically:

You have 5 players to start off with, so you have 5 players that can go in the first position.

That leaves you with 4 players. Any one of those 4 players can go in the second position.

And then there were 3 players. Any one of those 3 players can go in the third position.

2 to go! Pick your favorite player out of the 2 available to go in the fourth position.

And that leaves just one player who has to go last.

This can be modeled as: 5x4x3x2x1, or 5!, which equals 120 unique permutations.

User Damianodamiano
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6.2k points
4 votes

Answer:

i believe it is "5!"

Explanation:

1x2x3x4x5=120

but the answer is "5!" ( include the exclamation point)

hope this helps (again)

User Stenlytw
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6.0k points