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6
∑ 3n
n=2

a.2+3+4+5+6
b.3+6+9+12+15
c.6+9+12+15+18
d.3+6+9+12+15+18

User Gildardo
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Answer:

Explanation:

d.3+6+9+12+15+18 sum 6 terms multiple of 3

User Leesa
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