Answer:
0.03
Explanation:
The given question uses the concept of Conditional Probability. The general formula of conditional probability in terms of two events A and B is:

In the given case, the two events are:
LC = Event that someone has lung cancer
S = Event that someone is smoker
The formula in terms of these events will be:

Using the given values, we can find the probability that a random person is a smoker and has lung cancer P(S∩LC).

Therefore, the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC) is 0.03