1 Answer

Saranga Athukorale · Answer 1 · 2020-01-22T08:28:57+0000

Answer:

Option D.
$40\°$

Explanation:

we know that

The inscribed angle measures half that of the arc comprising

so

$m<QPS=(1)/(2)(minor\ arc\ QS)$

we have

$m<QPS=20\°$ ----> given problem

substitute

$20\°=(1)/(2)(minor\ arc\ QS)$

$40\°=(minor\ arc\ QS)$

Rewrite

$minor\ arc\ QS=40\°$

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