Question

A bag contains 1 blue, 2 green, and 3 red marbles, as shown. What is the probability of drawing a green marble out of the bag without looking?

Answer 1

The probability of drawing a green marble out of the bag without looking = 1/3

Explanation:

It is given that, a bag contains 1 blue, 2 green, and 3 red marbles

Therefore total number of marble in the bag = 1 + 2 + 3 = 6

To find the probability

Total number of marble = 6

Number of green marble = 2

The probability of drawing a green marble = 2/6 = 1/3

Answer 2

`P(G)= (1)/(3)`

EXPLANATION

The number of green marbles in the bag is

`n(G) = 2`

The total number of marbles in the bag is

`n(S)=1+2+3 = 6`

The probability of selecting a green marble from the bag without looking is

`P(G)= (n(G))/(n(S))`

Substitute the values to get,

`P(G)= (2)/(6)`

`P(G)= (1)/(3)`