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The line that contains the point Q( 1, -2) and is parallel to the line whose equation is

y - 4 = 2/3 (x - 3)

2 Answers

4 votes

In order for the line to be parallel it has to be the same slope. So basically you want to put the equation in slope intercept form Y=Mx+b. Do isolate the Y.

Answer

y-4=2/3(x-3)

y-4=2/3x-2

+4. +4

y=2/3x+2

User Romello
by
5.1k points
4 votes

Answer:

y + 2 = (2/3)(x - 1)

Explanation:

Two lines with the same slope are parallel; if two lines are parallel, they have the same slope.

Starting with the standard point-slope formula for the straight line,

y - k = m (x - h), where (h, k) is the given point, we get:

y -[-2] = (2/3)( x - 1), or

y + 2 = (2/3)(x - 1) This is the desired equation of the parallel line.

User Sean Gough
by
6.4k points