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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For one performance, 40 advance tickets and 15 same-day tickets were sold. The total amount paid for the tickets was $1325. What was the price of each kind of ticket?

User Fnostro
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1 Answer

4 votes

Answer:

advance tickets cost $20 each & same-day tickets cost $35 each

Explanation:

Let cost of advanced ticket be x and cost of same-day ticket be y. Now we can write 2 equations and solve them simultaneously.

"The combined cost of one advance ticket and one same-day ticket is $55":


x+y=55

and

"...40 advance tickets and 15 same-day tickets were sold. The total amount paid for the tickets was $1325":


40x+15y=1325

We solve for x in the first equation to get x = 55 - y and substitute this into 2nd equation and solve for y:


40(55-y)+15y=1325\\2200-40y+15y=1325\\-25y=1325-2200\\-25y=-875\\y=(-875)/(-25)=35

Now plugging in y = 35 into the first equation, we can solve for x:


x+y=55\\x+35=55\\x=55-35\\x=20

Hence, advance tickets cost $20 each & same-day tickets cost $35 each

User David Beaudway
by
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