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Solve the system of equations: y = 2x - 5, y=x^2- 5

A. (0, -5) and (2, - 1)
B. (0,5) and (2, 2)
C. (-1,-4) and (3, 4)
D. (-1.-7) and (4,3​

Solve the system of equations: y = 2x - 5, y=x^2- 5 A. (0, -5) and (2, - 1) B. (0,5) and-example-1
User Mike Eason
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1 Answer

5 votes

Answer:

A

Explanation:

both equation is y so

2x - 5 = x² - 5

2x = x²

0 = x² - 2x

0 = x(x-2)

x = 0

x = 2

for x = 0

y = 2x - 5

y = 0 - 5

y = -5

(0,-5)

for x = 2

y = 2x - 5

y = 2(2) - 5

y = -1

(2,-1)

User Raduation
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4.5k points