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Y=-x^2-10x+24 what is the u value of the vertex

User Jemlifathi
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1 Answer

3 votes

Answer:


\large\boxed{The\ vertex:\ (-5,\ 49)}

Explanation:


f(x)=ax^2+bx+c\\\\\text{The vertex}\ (h,\ k),\ \text{where}\ h=(-b)/(2a)\ \text{and}\ k=f(h).\\\\\text{We have:}\ y=-x^2-10x+24\to f(x)=-x^2-10x+24\\\\a=-1,\ b=-10,\ c=24.\\\\\text{Substitute:}\\\\h=(-(-10))/(2(-1))=(10)/(-2)=-5\\\\k=f(-5)=-(-5)^2-10(-5)+24=-25+50+24=49

User Steffen Funke
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