Question

What is the solution?

Answer 1

Answer: OPTION A

Explanation:

Apply the Quadratic formula, which is:

`x=(-b\±√(b^2-4ac))/(2a)`

In this case:

`a=1\\b=-6\\c=58`

Then, you must susbtitute these values into the quadratic formula, as shown below:

`x=(-(-6)\±√((-6)^2-4(1)(58)))/(2*1)`

`x=(6\±√(-196))/(2)`

Keep on mind that
`i=√(-1)`, then you can rewrite it as following:

`x=(6\±14i)/(2)\\\\\\x=(2(3\±7i))/(2)\\\\x=3\±7i\\\\x_1=3+7i\\x_2=3-7i`

Answer 2

A. {
`3+7i,3-7i`}

Explanation:

The given equation is
`x^2-6x+58=0`

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

`x=(-b\pm√(b^2-4ac) )/(2a)`

We substitute the given values to get;

`x=(--6\pm √((-6)^2-4(1)(58)) )/(2(1))`

`x=(6\pm √(36-232) )/(2)`

`x=(6\pm √(-196) )/(2)`

Recall that;

`√(-1)=i`

`x=(6\pm 14i)/(2)`

`x=3\pm 7i`

`x=3+7i` or
`x=3-7i`