Question

PLEASE HELP

A plane intersects a cylinder parallel to the cylinder’s bases. What’s the area of the resulting cross section? Use 3.14 for π. Round your answer to the nearest tenth

Answer 1

The area of the resulting cross section is
`78.5\ m^(2)`

Explanation:

we know that

The resulting cross section is a circle congruent with the circle of the base of cylinder

therefore

The area is equal to

`A=\pi r^(2)`

we have

`\pi=3.14`

`r=10/2=5\ m` -----> the radius is half the diameter

substitute the values

`A=(3.14)(5)^(2)=78.5\ m^(2)`