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Uranium-238 undergoes alpha decay. Therefore, uranium-238 will

A. Remain stable
B. Stay the same element
C. Release charged particles and no energy
D. None of the above

2 Answers

1 vote

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will

A. Remain stable

B. Stay the same element

C. Release charged particles and no energy

D. None of the above

The actual answer is that it will change into a different element altogether.

User NoobSter
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3 votes

Answer:

D.None of the above.

Step-by-step explanation:

We are given that uranium-238 undergoes alpha decay.

Therefore, uranium-238 change into into new element of atomic number 2 less and mass number 4 less and releasing an alpha particle because it undergoes alpha decay

U-238
\rightarrowan atome with atomic number 2 less and mass number 4 less+ helium particle with atomic number 2 and mass number 4

Alpha decay: When an element undergoes an alpha decay then it transform into an atom with atomic number 2 less and mass number 4 less due to emission of alpha particle (alpha particle means helium particle which have atomic number 2 and mass number 4)

Therefore, option A is false.

B. It is also false.Because a new atom is formed and there is no releasing of charged particle

C.There is no any releasing of charged particle and no energy.Hence, it is false.

Answer :D. None ob the above.

User Hvelarde
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