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Determine the graph of the polar equation r =6/2-2cos theta.

Determine the graph of the polar equation r =6/2-2cos theta.-example-1
Determine the graph of the polar equation r =6/2-2cos theta.-example-1
Determine the graph of the polar equation r =6/2-2cos theta.-example-2

2 Answers

5 votes

Answer:

D

Explanation:

edge

User Jordan Morris
by
5.9k points
6 votes

Answer:

Choice D is correct

Explanation:

The first step is to write the polar equation of the conic section in standard form by dividing both the numerator and the denominator by 2;


r=(3)/(1-cos(theta))

The eccentricity of this conic section is thus 1, the coefficient of cos θ. Thus, this conic section is a parabola since its eccentricity is 1.

The value of the directrix is determined as;

d = k/e = 3/1 = 3

The denominator of the polar equation of this conic section contains (-cos θ) which implies that this parabola opens towards the right and thus the equation of its directrix is;

x = -3

Thus, the polar equation represents a parabola that opens towards the right with a directrix located at x = -3. Choice D fits this criteria

User Aviomaksim
by
6.3k points
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