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1 vote
A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the blag, what is the
probability that the first marble will be green and the second will be red?

User Tropilio
by
7.2k points

1 Answer

4 votes

Answer:

number of green ÷ total number of marbles

times by

number of red ÷ total number of marbles left

so

(3/9) × (2/8) = (1/12)

User Razvan Caliman
by
7.0k points