Question

A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the blag, what is the
probability that the first marble will be green and the second will be red?

Answer 1

number of green ÷ total number of marbles

times by

number of red ÷ total number of marbles left

so

(3/9) × (2/8) = (1/12)