Question

what was the initial pressure of 14.8 mL of gas at 75.5 C , when it occupied a volume of 16.5 mL at 70.2 C and 101.3 kPa?

Answer 1

1038.96 kPa

Step-by-step explanation:

We’ll use the ideal gas law; P1V1/T1 = P2V2/T2

P1*14.8/75.5 = 101.3*16.5/70.2

P1 = (101.3 * 16.5 * 75.5) / (70.2 *14.8)

P1 = 1038.96