Question

if i contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 k, what is the pressure inside the container? ​

Answer 1

`1.66\cdot 10^5 Pa`

Step-by-step explanation:

The ideal gas equation states that:

`pV=nRT`

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

`n = 3 mol` (number of moles)

`V=60 L=60\cdot 10^(-3) m^3` (gas volume)

`T=400 K`

So we can solve the formula for p, the pressure of the gas:

`p=(nRT)/(V)=((3 mol)(8.314 J/mol K)(400 K))/(60\cdot 10^(-3) m^3)=1.66\cdot 10^5 Pa`