You could take a 2 out of every term
2(x^2 + 5x + 6) = 0
You would then need to find two numbers that add to 5 and multiply to 6
In this case, those numbers are 2 and 3
2(x + 3)(x + 2) = 0
Then to find the roots (or what x equals), set each term equal to 0
(2=0) (reject)
x + 3 = 0
x = -3
x + 2 = 0
x = -2
{-2,-3}