Question

Factor x^3 -4x^2 -3x +18 =0

Given that 4 is a zero

A (x-2) (x-3) (x+3)=0
B (x-2) (x-3)^2 =0
C (x-2) (x- sqrt 3)(x+ sqrt 3) =0
D (x-2) (x-3)^2 =0

Answer 1

none of the above

Explanation:

A graphing calculator shows the zeros to be x=-2, and a double zero at x=3. Hence the factorization is ...

(x +2)(x -3)^2 = 0

The premise that 4 is a zero is incorrect, and none of the answer choices include (x+2) as a factor. The problem is unworkable as written here.