Question

50 POINTS! Chipping from the rough, a golfer sends the ball at an angle of 54° with an initial velocity of 13m/s, how far down the green did the ball go?

Answer 1

Range equation:

`x=\frac{{v_i}^2\sin2\theta}g`

This ball travels a distance of

`x=(\left(13(\rm m)/(\rm s)\right)^2\sin108^\circ)/(9.8(\rm m)/(\mathrm s^2))=16\,\mathrm m`