Question

The vertices of triangle ABC are A(2,3), B(–1,2), and C(3,1). If ΔDEF ∼ ΔABC and DE = 4AB, what is the length of EF? The answers are √10,√17,4√10,4√17

Answer 1

EF = 4BC

BC = sqrt ((3-(-1)^2 +(1-2)^2)

=》 BC = sqrt (4^2 +(-1)^2) = sqrt17

=》 EF = 4BC = 4(sqrt 17)

Answer 2

D. 4√17

Explanation: