Answer:
The solution set is {-6, -1}.
Explanation:
Next time, please use " ^ " to denote exponentiation: y=x^2 + 7x + 6.
This function is easily factored: y = (x + 1)(x + 6).
Setting it = to 0 and solving for x yields the zeros {-1, -6}, which are also the "solutions."
You might consider graphing this function even tho' we already have the solutions here. The y-intercept of y = x^2 + 7x + 6 is (0, 6), and, as we have already seen, the zeros / roots / solutions are (-1, 0) and (-6, 0).
The vertex is found by evaluating x = -b/(2a), which here is x = -(7) / (2*1) = -7/2. Subbing -7/2 for x into y=x^2 + 7x + 6 yields the y-value of the vertex.