Question

What is the probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube? Assume the number cubes are fair and have six sides. Express your answer as a fraction in simplest form.

Answer 1

1/36

Explanation:

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is 1/36

Explanation:

There are total 6 possible outcomes of rolling a six sided fair cube. Therefore, the probability of rolling each number (1,2,3,4,5,6) is fair = 1/6

In this way,

The probability of rolling a 5 on the first number cube = p(A) = 1/6

The probability of rolling a 6 on the second number cube = p(B) = 1/6

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is = p(A) * p(B) = 1/6*1/6 = 1/36

Answer 2

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is 1/36

Explanation:

There are total 6 possible outcomes of rolling a six sided fair cube. Therefore, the probability of rolling each number (1,2,3,4,5,6) is fair = 1/6

In this way,

The probability of rolling a 5 on the first number cube = p(A) = 1/6

The probability of rolling a 6 on the second number cube = p(B) = 1/6

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is = p(A) * p(B) = 1/6*1/6 = 1/36