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2 votes
Given h(f)=-2(t+5)^2 +4, find h(-8)

User Pio Pio
by
8.1k points

2 Answers

4 votes

Answer:

h(-8) = 22

Explanation:

Plug -8 in for t and simplify...

h(-8) = 2(-8 + 5)² + 4

h(-8) = 2(-3)² + 4

h(-8) = 2(9) + 4

h(-8) = 18 + 4

h(-8) = 22

User SumanKalyan
by
7.9k points
2 votes

Answer:

Explanation:

Given h(f)=-2(t+5)^2 +4

There is an intermediate step which is

h(f) = -2(f + 5)^2 + 4

h(-8) = -2(-8 + 5)^2 + 4

h(-8) = -2(-3)^2 + 4

h(-8) = -2(9) + 4

h(-8) = -18 + 4

h(-8) = - 14

User Awright
by
8.6k points

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