Answer:
f^ - 1 (x) = x/3 + 1/3 is not the inverse function of f(x) = 3x + 1
Explanation:
F(x) = 3x + 1
Inverse:
x = 3y + 1
3y = x - 1
y = x/3 - 1/3 or f^ - 1 (x) = x/3 - 1/3
so
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