Answer:
The exact form of
is
![-√(2)+1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5sxqoztpvyjueqa3tmzvp68zav0s8694fc.png)
Explanation:
We need to find the exact value of
using half angle identity.
Since,
is not an angle where the values of the six trigonometric functions are known, try using half-angle identities.
is not an exact angle.
First, rewrite the angle as the product of
and an angle where the values of the six trigonometric functions are known. In this case,
can be written as ;
![((1)/(2))(7\pi)/(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/al6t7h7rh6hjucteaf768mk3q5dp0qnldy.png)
Use the half-angle identity for tangent to simplify the expression. The formula states that
![\tan (\theta)/(2)=(\sin \theta)/(1+ \cos \theta)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ukmrz2o5gq44mie0ufcsf8s5ed5axbkgul.png)
![=(\sin((7\pi)/(4)))/(1+ \cos ((7\pi)/(4)))](https://img.qammunity.org/2020/formulas/mathematics/high-school/ezrdl3pwd138mmeq3yhbovjq5rdz8ogt1k.png)
Simplify the numerator.
![=((-√(2))/(2))/(1+ \cos ((7\pi)/(4)))](https://img.qammunity.org/2020/formulas/mathematics/high-school/by69arapvgud4jlsv2lqgvgpru9aaqzugf.png)
Simplify the denominator.
![=((-√(2))/(2))/((2+√(2))/(2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/cn5989b8enhxdxoiowry40fyxccl605r13.png)
Multiply the numerator by the reciprocal of the denominator.
![(-√(2))/(2)* (2)/(2+√(2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/wc68b84uep425429uepz0b56u7i0bcz100.png)
cancel the common factor of 2.
![(-√(2))/(1)* (1)/(2+√(2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/ura68n40ksioqexnl1trz8hzb06z3sibuh.png)
Simplify,
![(-√(2)(2-√(2)))/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bmgz3lxx8gsv3du1640d74xpruziwx8k12.png)
![(-(2√(2)-√(2)√(2)))/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/x17fe4o36t5c75wz3o7014chfygqtnjrd9.png)
![(-(2√(2)-2))/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/m3f4eiq8ug41bw1i5vdwav2r4g9xp2rdyh.png)
simplify terms,
![-√(2)+1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5sxqoztpvyjueqa3tmzvp68zav0s8694fc.png)
Therefore, the exact form of
is
![-√(2)+1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5sxqoztpvyjueqa3tmzvp68zav0s8694fc.png)