Question

Please help me asap!

Answer 1

`(7x + 7)/((x-3)(x+4))`

Excluded values are 3 and -4

Explanation:

To simplify the expression multiply to create a common denominator.

Multiply the first fraction by (x-3) and the second fraction by (x+4).

`(3)/(x+4) + (4)/(x-3)\\\\(3(x-3))/((x+4)(x-3)) + (4(x+4))/((x-3)(x+4))`

`(3(x-3))/((x+4)(x-3)) + (4(x+4))/((x-3)(x+4)) \\\\(3(x-3) + 4(x+4))/((x-3)(x+4))\\\\(3x - 9 + 4x + 16)/((x-3)(x+4))\\\\(7x + 7)/((x-3)(x+4))`

Excluded values are values which make the denominator 0. This means (x-3)(x+4) cannot be 0. This means x cannot be 3 or -4. These are excluded values.