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Which method is most efficient method to use to solve 2x^2+4x-7=0

1 Answer

5 votes

Answer:

Use the quadratic formula

Explanation:

Use the quadratic formula

For a quadratic function of the form:


ax ^ 2 + bx + c

Where a, b and c are the real coefficients of the polynomial

Then, for


2x^2+4x-7=0\\a = 2\\b = 4\\c = -7

The solutions are:


x_1 = (-b+√(b^2-4ac))/(2a)\\\\x_2 = (-b-√(b^2-4ac))/(2a)


x_1 = (-4+√(4^2-4(2)(-7)))/(2(2))\\\\x_2 = (-4-√(4^2-4(2)(-7)))/(2(2))\\\\x_1 = (-2+3√(2))/(2)\\\\x_2 = (-2-3√(2))/(2)

User Blackdad
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