Question

Which method is most efficient method to use to solve 2x^2+4x-7=0

Answer 1

Use the quadratic formula

Explanation:

Use the quadratic formula

For a quadratic function of the form:

`ax ^ 2 + bx + c`

Where a, b and c are the real coefficients of the polynomial

Then, for

`2x^2+4x-7=0\\a = 2\\b = 4\\c = -7`

The solutions are:

`x_1 = (-b+√(b^2-4ac))/(2a)\\\\x_2 = (-b-√(b^2-4ac))/(2a)`

`x_1 = (-4+√(4^2-4(2)(-7)))/(2(2))\\\\x_2 = (-4-√(4^2-4(2)(-7)))/(2(2))\\\\x_1 = (-2+3√(2))/(2)\\\\x_2 = (-2-3√(2))/(2)`