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18 *2^5t = 261 what is the solution of the equation

18 *2^5t = 261 what is the solution of the equation-example-1
User Luuk
by
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1 Answer

8 votes
8 votes

Answer:

0.772

Explanation:

Original equation:


18 * 2^(5t)=261

Divide both sides by 18


2^(5t) = 14.5

Rewrite in logarithmic form (
b^x=c \implies log_bc=x)


log_214.5 = 5t

Divide both sides by 5


(log_214.5)/(5)=t

Rewrite the equation so that base is 10 using change of base formula:
log_ba = (log_na)/(log_nb)


(((log14.5)/(log2)))/(5)=y

Keep, change, flip


(log14.5)/(log2)*(1)/(5) = (log14.5)/(5 * log2)

Use a calculator to approximate log14.5 and log2


(1.161368)/(5 * 0.301029996) = t

Multiply in denominator


(1.161368)/(1.505149978) = t

Divide two values


t\approx 0.771596

Round to nearest thousandth


t\approx 0.772

User Adebasi
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