Answer:
Reflection across the line y=x followed by translation 10 units to the right and 4 units up.
Explanation:
Triangle ABC has vertices at points A(-6,2), B(-2,6) and C(-4,2).
1. The reflection across the line y=x has the rule
(x,y)→(y,x).
Thus,
- A(-6,2)→A''(2,-6);
- B(-2,6)→B''(6,-2);
- C(-4,2)→C''(2,-4).
2. The translation 10 units to the right and 4 units up has the rule
(x,y)→(x+10,y+4).
Thus,
- A''(2,-6)→A'(12,-2);
- B''(6,-2)→B'(16,2);
- C''(2,-4)→C'(12,0).
Points A'B'C' are exactly the vertices of the triangle A'B'C'.