Question

If f(x) = –2x + 7 and g(x) = x2 – 2, what is [f o g](3)?

Answer 1

The answer is A. -7 on edge :)

Answer 2

`(f\circ g)(3)=-7`

Explanation:

The given functions are;

`f(x)=-2x+7`

and

`g(x)=x^2-2`

We need to first of all find
`(f\circ g)(x)`

`(f\circ g)(x)=f(g(x))`

`(f\circ g)(x)=f(x^2-2)`

`(f\circ g)(x)=-2(x^2-2)+7`

`(f\circ g)(x)=-2x^2+4+7`

`(f\circ g)(x)=-2x^2+11`

We now plug in x=3

`(f\circ g)(3)=-2(3)^2+11`

`(f\circ g)(3)=-18+11`

`(f\circ g)(3)=-7`