Question

Use the x-intercept method to find all real solutions of the equation.
x^2-9x^2+23x+15=0

Answer 1

b.
`x=1,3,\:or\:5`

Explanation:

The given equation is;

`x^3-9x^2+23x-15=0`

To solve by the x-intercept method we need to graph the corresponding function using a graphing tool.

The corresponding function is

`f(x)=x^3-9x^2+23x-15`

The solution to
`f(x)=x^3-9x^2+23x-15=0` is where the graph touches the x-axis.

We can see from the graph that; the x-intercepts are;

(1,0),(3,0) and (5,0).

Therefore the real solutions are:

`x=1,3,\:or\:5`