Question

Use the x-intercept method to find all real solutions of the equation.
x^3-7x^2+4x+12=0

Answer 1

the answer is c for apex

Explanation:

Answer 2

a.
`x=-1,2,\:or\:6`

Explanation:

The given equation is

`x^3-7x^2+4x+12=0`

To find all real solutions using the x-intercept method, we to graph the corresponding function using a graphing tool.

The corresponding function is;

`f(x)=x^3-7x^2+4x+12`

The real solutions to
`x^3-7x^2+4x+12=0`, are the x-intercepts of the graph of the corresponding function.

From the graph the x-intercepts are

(-1,0),(2,0) and (6,0).

Therefore the real solutions are

`x=-1,2,\:or\:6`