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26 votes
26 votes
Can someone help me with this pls

Can someone help me with this pls-example-1
User Mourad MAMASSI
by
3.1k points

2 Answers

17 votes
17 votes

Answer:

x = 1/3 or x = -2/3

Explanation:

Let's solve your equation step-by-step.

9x2+3x−2=0

For this equation: a=9, b=3, c=-2

9x2+3x+−2=0

Step 1: Use quadratic formula with a=9, b=3, c=-2.


x=(-b\pm√(b^2-4ac) )/(2a)


x=(-(3)\pm√((3)^2-4(9)(-2)) )/(2(9))


x=(-3\pm√(81) )/(18)

x = 1/3 or x = -2/3

User Kritya
by
3.0k points
13 votes
13 votes


\huge\text{Hey there!}


\huge\textbf{What is the quadratic formula?}


\rm{x = (-b \pm √(b^2 - 4ac))/(2a)}


\textsf{Or even}


\rm{ax^2 + bx + c = 0}


\huge\textbf{What are we looking for?}


\rm{9x^2 + 3x - 2 = 0}


\huge\textbf{What are the labels in the equation?}


\mathsf{a \rightarrow 9}\\\\\mathsf{b\rightarrow 3}\\\\\mathsf{c \rightarrow -2}


\huge\textbf{Solving for your equation:}


\rm{x = (-(3)\pm √(3^2 - 4(9)(-2)))/(2a)}


\huge\textbf{Simplify it:}


\rm{x = (-3\pm √(81))/(18)}


\rm{x = (1)/(3)\ or\ x = - (2)/(3)}


\huge\textbf{Therefore, your answer should be:}


\huge\boxed{\frak{\mathsf{x} = (1)/(3)\ or\ \mathsf{x} = - (2)/(3)}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}

~
\frak{Amphitrite1040:)}

User Kent Rancourt
by
2.9k points