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Find the polar equation of the conic with the focus at the pole, directrix y = -6, and eccentricity 4 (picture provided)

Find the polar equation of the conic with the focus at the pole, directrix y = -6, and-example-1
User Elssar
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2 Answers

2 votes

Answer:

b on edge

Explanation:

User Sandorfalot
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4.6k points
5 votes

Answer:

Choice B is correct

Explanation:

The eccentricity of the conic section is given as 4 and thus the conic section is a hyperbola. Hyperbolas are the only conic sections with an eccentricity greater than 1.

Next, the directrix of this hyperbola is located at y = -6 implying that the hyperbola will be opening upwards. Consequently, the polar equation of this hyperbola will be of the form;


r=(k)/(1-4sin(theta))

The value of k in the numerator is the product of eccentricity and the absolute value of the directrix;

k= 4*6 = 24

The polar equation is thus given by alternative B

User Steffenhk
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