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Need help please, does any one know how to do this​

Need help please, does any one know how to do this​-example-1
User Cory Trese
by
7.3k points

1 Answer

7 votes

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

(-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

(6 -u)/(u +2)

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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

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3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

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4) You can also multiply numerator and denominator by some constant, say 3:

-(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

(1+x^2)(6 -u)/((1+x^2)(u+2))

User Kevin Baker
by
6.3k points
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