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3 votes
A ball is thrown vertically in the air with an initial velocity of 60 feet per second from an initial height of 6 feet. The equation describing the height of the ball at any time is s = -16t^2 +60t+6.

1. how long did it take for the ball to reach its height point?
2. How high did the ball go?

User Sayed
by
5.4k points

1 Answer

6 votes

hight * velocity =

3600ft hight of 3ft

User Ooberdan
by
5.1k points
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