Question

What are the zeros of f(x)=x^2-8x+16

Answer 1

4 and 4

Explanation:

The quadratic f(x)=x^2-8x+16 factors into f(x) = (x - 4)².

Setting this result = to 0, we obtain the double root x = 4, x = 4.

Answer 2

zero of the function is 4

Explanation:

`f(x)=x^2-8x+16`

To find the zeros , we replace f(x) with 0

`0=x^2-8x+16`

Factor the right side of the equation and solve for x

`0=x^2-8x+16` product is 16 and sum is 8

-4 times -4 is 16

-4 plus -4 is -8, the factors are -4 and -4

`0=(x-4)(x-4)`

set each factor =0 and solve for x

x-4 =0, x=4