Question

Please help. was due 2 days ago

Answer 1

`x=-(1)/(2),(5)/(2)`

Explanation:

1) Split the second term in
`4{x}^(2)-8x-5` into two terms.

1- Multiply the coefficient of the first term by the constant term.

`4* -5=-20` to -8 and multiply to -−20?

2 and −10

3 - Split -8x as the sum of 2x and -10x.

`4x^2+2x-10x-5`

2) Factor out common terms in the first two terms, then in the last two terms.

`2x(2x+1)-5(2x+1)=0`

3) Factor out the common term
`2x+1`.

`(2x+1)(2x-5)=0`

4) Solve for
`x`.

1 - Ask: When will (2x+1)(2x-5) equal zero?

When 2x + 1 = 0 or 2x - 5 = 0

2 - Solve each of the 2 equations above.

`x=-(1)/(2),(5)/(2)`